A basketball player has a 70% accuracy rate for making free throws. Mark thought that each attempt was independent and the probability stayed at 70% for this player.

During a game, this player was fouled and given the chance to take two free throws.

P left parenthesis X equals k right parenthesis equals left parenthesis 1 minus p right parenthesis to the power of k minus 1 end exponent p

Using the geometric distribution formula, what is the probability that this player misses his first free throw, but makes the second one? Answer choices are rounded to the hundredths place. 0.50
b.)
0.70
c.)
0.21
d.)
0.30