Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Calculate the Molarity of 15.4 g of sucrose (C12H22O11) in 74.0 mL of solution

Sagot :

samueladesida43

The molarity of 15.4 g of sucrose (C12H22O11) in 74.0 mL of solution is 0.61M

HOW TO CALCULATE MOLARITY:

  • The molarity of a solution can be calculated by dividing the number of moles by the volume as follows:

Molarity (M) = no. of moles (mol) ÷ volume (L)

  • According to this question, 15.4 g of sucrose (C12H22O11) is said to be in 74.0 mL of solution. The mass of sucrose must be converted to moles by dividing by its molar mass:

Molar mass of C12H22O11 = 12(12) + 1(22) + 16(11)

= 144 + 22 + 176

= 342g/mol

  • no. of moles = 15.4g ÷ 342g/mol

  • no. of moles = 0.045mol

Volume = 74mL = 74/1000 = 0.074L

Molarity = 0.045mol ÷ 0.074L

Molarity = 0.61M

  • Therefore, the molarity of 15.4 g of sucrose (C12H22O11) in 74.0 mL of solution is 0.61M.

Learn more: https://brainly.com/question/15948514?referrer=searchResults

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.