Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Calculate the Molarity of 15.4 g of sucrose (C12H22O11) in 74.0 mL of solution

Sagot :

samueladesida43

The molarity of 15.4 g of sucrose (C12H22O11) in 74.0 mL of solution is 0.61M

HOW TO CALCULATE MOLARITY:

  • The molarity of a solution can be calculated by dividing the number of moles by the volume as follows:

Molarity (M) = no. of moles (mol) ÷ volume (L)

  • According to this question, 15.4 g of sucrose (C12H22O11) is said to be in 74.0 mL of solution. The mass of sucrose must be converted to moles by dividing by its molar mass:

Molar mass of C12H22O11 = 12(12) + 1(22) + 16(11)

= 144 + 22 + 176

= 342g/mol

  • no. of moles = 15.4g ÷ 342g/mol

  • no. of moles = 0.045mol

Volume = 74mL = 74/1000 = 0.074L

Molarity = 0.045mol ÷ 0.074L

Molarity = 0.61M

  • Therefore, the molarity of 15.4 g of sucrose (C12H22O11) in 74.0 mL of solution is 0.61M.

Learn more: https://brainly.com/question/15948514?referrer=searchResults

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.