Answered

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(x+1)^2+(x-1)^2-2x(x+2)=0

Sagot :

renknee

Answer:

x = 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

  • [tex](x+1)^2+(x-1)^2-2x(x+2)=0[/tex]
  • [tex]x^2 + 2x + 1 + x^2 - 2x + 1 -2x^2 -4x = 0[/tex]
  • [tex](x^2 + x^2-2x^2) + (2x-2x-4x)+(1+1)=0[/tex]
  • [tex]-4x + 2 = 0[/tex]

Step 2: Subtract 2 from both sides.

  • [tex]-4x + 2 - 2 = 0 - 2[/tex]
  • [tex]-4x = -2[/tex]

Step 3: Divide both sides by -4.

  • [tex]\frac{-4x}{-4} = \frac{-2}{-4}[/tex]
  • [tex]x = \frac{1}{2}[/tex]
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