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Using the stoichiometry of the reaction, the mass of mercury produced is 51.5 g.

The equation of the reaction is shown properly as;

2HgO(s) ------> 2Hg(s) + O2(g)

Number of moles of HgO = mass/molar mass

Molar mass of HgO = 216.591 g

Number of moles of HgO = 27.7 g/216.591 g/mol = 0.128 moles

From the reaction equation;

2 mols of HgO yields 1 mole of Hg

0.128 moles of  HgO yields 2 mols ×  0.128 moles /1 mol = 0.256 moles

Hence mass of mercury =  0.256 moles × 201 g/mol = 51.5 g

Learn more about stoichiometry: https://brainly.com/question/9743981

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