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Find the area of ABF. Round the area to the nearest whole number if necessary.

Find The Area Of ABF Round The Area To The Nearest Whole Number If Necessary class=

Sagot :

danielgeyfman

Answer:

[tex]6[/tex]

Step-by-step explanation:

We see that the triangle is a right triangle. We need to find the lengths of the two legs to find the area, then. Let's start with AB.

[tex]AB=\sqrt{(3-1)^2+(0-(-2))^2}=\sqrt{2^2+2^2}=\sqrt{8}=2\sqrt{2}[/tex]

Now, we do the other leg.

[tex]\sqrt{(1-4)^2+(-2-(-5))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}[/tex].

That will make the area [tex]b*h/2=2\sqrt{2}*3\sqrt{2}/2=6*2/2=6[/tex]

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