ramkrishnaneupane59
Answered

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Sagot :

msm555

Answer:

Solution given:

2:centroid=[tex]\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3}[/tex]

=[tex]\frac{1+3+5}{3},\frac{2+7+3}{3}=(3,4)[/tex]

4:

Slope:[tex]\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{5-3}=2[/tex]

3;

perpendicular distance =[tex]\frac{ax_1+by_1+c}{\sqrt{a²+b²}}[/tex]

[tex](x_1,y_1)=(3,-2)[/tex]

4x-3y+2=0

comparing above equation with ax+by+c =0 ,we get

a=4

b=-3

c=2

d=[tex]\frac{4*3+(-3*-2)+2}{\sqrt{4²+(-3)²}}[/tex]

=4 units

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