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Sagot :
1. Take the coordinates.
a) (1,10) and (0,0)
2. Find slope.
m = y - y1
x - x1
m = 0 - 10
0 - 1
m = -10/-1
m = 10
3. Write the eqn.
y - y1 = m(x - x1) at (1, 10)
y - 10 = 10(x - 1)
y = 10x - 10 + 10
y = 10x
Answer:
taking two points :
Let one point be [tex](x_1,y_1)[/tex]=(0,0)
and another point be[tex](x_2,y_2)[/tex]= (1,10)
now
we have equation of a straight line is:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
y-0=[tex]\frac{10-0}{1-0}(x-0)[/tex]
y=10x is a required equation
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