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Sagot :
Applying pythagorean theorem:-
[tex]\\ \sf\longmapsto 8^2-5^2=b^2[/tex]
[tex]\\ \sf\longmapsto 64-25=b^2[/tex]
[tex]\\ \sf\longmapsto b^2=39[/tex]
[tex]\\ \sf\longmapsto b=\sqrt{39}[/tex]
[tex]\\ \sf\longmapsto b=6.24[/tex]
Answer:
• from pythogras theorem:
[tex]{ \rm{ {c}^{2} = {a}^{2} + {b}^{2} }} \\ [/tex]
a → 5 km
c → 8 km
[tex]{ \tt{ {8}^{2} = {5}^{2} + {b}^{2} }} \\ \\ { \tt{ {b}^{2} = {8}^{2} - {5}^{2} }} \\ \\ { \tt{ {b}^{2} = 39}} \\ \\ { \tt{ \: b = \sqrt{39} = 6.2 \: km }}[/tex]
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