lewik326
Answered

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prove algebraically that the recurring decimal 0.72 =8/11

Sagot :

Answer:

see explanation

Step-by-step explanation:

We require 2 equations with the recurring decimal placed after the decimal point.

let x = 0.7272.... (1) ← multiply both sides by 100

100x = 72.7272... (2)

Subtract (1) from (2) thus eliminating the recurring decimal

99x = 72 ( divide both sides by 99 )

x = [tex]\frac{72}{99}[/tex] = [tex]\frac{8}{11}[/tex]

jahrule67

Answer:

true

Step-by-step explanation:

because 8÷11=0.72

72÷10

=8÷11

=0.72

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