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(3x-3)^2 + (x+4)(x-1)

Please help... I have no clue what I'm doing and it's due in tomorrow. Thanks :)

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Answer:

[tex] {(3x - 3)}^{2} + (x + 4)(x - 1) \\ = {(3x)}^{2} - 2 \times 3x \times 3 + {3}^{2} + ( {x}^{2} - x + 4x - 4) \\ = {(3x)}^{2} - 18x + 9 + {x}^{2} + 3x - 4 \\ = 9 {x}^{2} + {x}^{2} - 18x + 3x + 9 - 4 \\ = 10 {x}^{2} - 15x + 5 \\ thank \: you[/tex]

Answer:

10x^2-15x-5

Step-by-step explanation:

(3x-3)^2 + (x+4)(x-1)

9x^2-18x+9+x^2+3x-4

10x^2-15x+5

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