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If 35.0 g of CH₃OH (MM = 32.0 g/mol) are dissolved in 500.0 mL of solution, what is the concentration of CH₃OH in the solution?

Sagot :

Considering the definition of molarity, the concentration of CH₃OH in the solution is 2.1875 [tex]\frac{moles}{liter}[/tex].

Molarity is a measure of concentration that indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

On the other hand, molar mass is the amount of mass that a substance contains in one mole.

Being the molar mass of CH₃OH 32.0 g/mol, then the number of moles that 35 g of the compound contain is calculated as:

[tex]35 gramsx\frac{1 mole}{32 grams} =[/tex] 1.09375 moles

If 1.09374 moles of CH₃OH are dissolved in 500.0 mL= 0.500 L (being 1000 mL= 1 L) of solution, the molarity can be calculated as:

[tex]Molarity=\frac{1.09375 moles}{0.500 L}[/tex]

Solving:

Molarity= 2.1875 [tex]\frac{moles}{liter}[/tex]

Finally, the concentration of CH₃OH in the solution is 2.1875 [tex]\frac{moles}{liter}[/tex].

Learn more about molarity with this example:

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