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help me with this one. anyone?​

Help Me With This One Anyone class=

Sagot :

bosm93

Answer:

3/5

Step-by-step explanation:

Firstly we will substitue x = 0 and we will realise that we have 0 in denominator. we will use Lhopitals rule.

[tex]\frac{d}{dx} sin(3x)(cos(3x) = 3cos(6x)\\\frac{d}{dx} 5x = 5\\ \lim_{x \to \infty} \frac{3cos(6*x)}{5} = \frac{3cos(0)}{5} = \frac{3}{5}[/tex]