Answered

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Find the time during the which €3600 gives an interest of € 1080 at the rate 6% per annum

Sagot :

himaruanuk

Answer:

5 years

Step-by-step explanation:

[tex]interest = \frac{prt}{100} [/tex]

[tex]1080 = \frac{3600 \times 6 \times t}{100} [/tex]

[tex] \frac{1080 \times 100}{3600 \times 6} = t[/tex]

108000/21600 = t

time = 5 years

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