Roqhayakhazi
Answered

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A spelunker explores a new underground cave. He descends into the cave at a rate of 4 feet per minute. What is the change in position of the spelunker after 50 minutes?

Sagot :

ronye47

Answer:

4 * 50 = 200

Step-by-step explanation:

Because he is descending at a rate of 4 feet every minute, after 50 minutes he is 200 feet down.

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