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Sagot :
In long division a polynomial is divided by another polynomial with a lower degree
- The two factors are; (x² - x - 12) and (x + 11)
Reason:
The given function is presented as follows;
x³ + 10·x² - 23·x - 132
A factor of the function is (x + 11)
By long division, we have;
Quotient; x² - x - 12
[tex]{}[/tex] (x³ + 10·x² - 23·x - 132) ÷ (x + 11)
[tex]{}[/tex] x³ + 11·x²
[tex]{}[/tex] -x² - 23·x - 132
[tex]{}[/tex] -x² - 11·x
[tex]{}[/tex] -12·x - 132
[tex]{}[/tex] -12·x - 132
[tex]{}[/tex] 0
Therefor, we have the two factors, are (x² - x - 12) and (x + 11)
Where;
(x² - x - 12) = (x - 4)·(x + 3)
Therefore, we have;
(x² - x - 12) × (x + 11) = x³ + 10·x² - 23·x - 132
Learn more about long division here;
https://brainly.com/question/12562913
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