Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I REWARD BRAINLIEST
NEED ANSWER IN LIKE LESS THAN 10 MIN! or 10 min exact

PLEASE HELP ASAP I REWARD BRAINLIEST NEED ANSWER IN LIKE LESS THAN 10 MIN Or 10 Min Exact class=

Sagot :

djtwinx017
Given 3x + 2y = 6 and the point (6, -3):

Transform the equation into slope-intercept form:

3x + 2y = 6

3x - 3x + 2y = - 3x + 6

2y = -3x + 6

Divide both sides by 2:

2y/2 = (-3x + 6)/2

y = -3/2x + 6 (slope-intercept form)

Next, to find the line perpendicular to the original equation:

By definition, perpendicular lines have negative reciprocals. This means that if you multiply the slope of the original equation with the slope of perpendicular line, it will have a product of -1.

The slope of the original equation is -3/2. This means that the negative reciprocal must be 2/3. Therefore, the slope of the perpendicular line is 2/3.

Next, we’ll use the given point (6,-3) and slope (2/3) to find out what the y-intercept is:

y = mx + b

-3 = 2/3(6) + b

-3 = 4 + b

-3 - 4 = 4 - 4 + b

-7 = b

Therefore, the y-intercept is -7.

We can establish the linear equation of the line perpendicular to 3x + 2y = 6:

y = 2/3x - 7
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.