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(4x + 3)(4x - 3)
Help pls

Sagot :

Answer:

[tex]16x^2-9[/tex]

Step-by-step explanation:

[tex]\left(4x+3\right)\left(4x-3\right)[/tex]

We´ll Apply Difference Two Squares Formula:

  • [tex]\left(a+b\right)\left(a-b\right)=a^2-b^2[/tex]

[tex]\longmapsto[/tex] [tex]\left(4x+3\right)\left(4x-3\right)[/tex]

[tex]\longmapsto[/tex] [tex]\left(4x\right)^2-3^2[/tex]

Apply exponent rule:

  • [tex]\left(a\times \:b\right)^n=a^nb^n[/tex]

[tex]\longmapsto[/tex] [tex]4^2x^2-3^2[/tex]

[tex]\longmapsto[/tex] [tex]16x^2-9[/tex]

_________________________

riyasinghqrtt

Answer:

16x^2 - 9

Step-by-step explanation:

(4x + 3)(4x - 3)

Using identity, (a + b) (a - b) = a^2 - b^2

here, a = 4x + 3 and b = 4x - 3,

therefore,

=> (4x) ^2 - (3)^2

=> 16x^2 - 9... ans

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