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How do you solve 1/4(x+5)^2-1=3 in steps?

Sagot :

Answer:

[tex]{ \tt{ \frac{1}{4} (x + 5) {}^{2} - 1 = 3 }} \\ \\ { \tt{ \frac{1}{4} {(x + 5)}^{2} = 4 }} \\ \\ { \tt{ {(x + 5)}^{2} = 16 }} \\ \\ { \tt{ \sqrt{ {(x + 5)}^{2} } = \sqrt{16} }} \\ \\ { \tt{x + 5 = ±4}} \\ \\ { \tt{x = ±4 - 5}} \\ \\ { \boxed{ \tt{ \: \: x = {}^{ - }1 \:or \:-9 }}}[/tex]

Heather

Answer:

x = -1, -9

Step-by-step explanation:

given:

1/4(x+5)^2-1=3

rewriting:

[tex]\frac{1}{4} (x+5)^2-1=3[/tex]

add 1 to both sides:

[tex]\frac{1}{4} (x+5)^2 = 4[/tex]

divide both sides by 1/4:

[tex](x+5)^2 = 16[/tex]

square root both sides:

[tex]x + 5 = + / - 4[/tex]

subtract 5 from both sides, we now have two equations to solve:

x = - 5 - 4                     x = - 5 + 4

x = -9                                x = - 1

answer:

x = -1, -9

Hopefully this helps, have a nice day! :D

Edit: The other answer forgot to solve for when 4 is negative

Edit #2: They have fixed it now

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