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Sagot :
Answer:
• Considering ax + by = -7
[tex]{ \tt{ax + by = - 7}} \\ \\ { \tt{(a \times 2) + (b \times - 1) = - 7}} \\ \\ { \boxed{ \tt{2a - b = - 7 \: - - - eqn \{1 \}}}}[/tex]
• make b the subject of eqn{1}
[tex]{ \tt{b = 2a + 7 - - - eqn \{2 \}}}[/tex]
• considering 2ax - 3by = 1
[tex]{ \tt{2ax - 3by = 1}} \\ \\ { \tt{(2a \times 2) - (3b \times - 1) = 1}} \\ \\ { \boxed{ \tt{4a + 3b = 1 - - - eqn \{3 \}}}}[/tex]
• substitute b in eqn{3} with b from eqn{2}
[tex]{ \tt{4a + 3(2a + 7) = 1}} \\ \\ { \tt{4a + 6a + 21 = 1}} \\ \\ { \tt{10a = - 20}} \\ \\ { \boxed{ \boxed{ \tt{ \: \: a = - 2 \: \: }}}}[/tex]
• find b using eqn{2}
[tex]{ \tt{b = 2a + 7}} \\ \\ { \tt{b = (2 \times - 2) + 7}} \\ \\ { \tt{b = - 4 + 7}} \\ \\ { \boxed{ \boxed{ \tt{ \: \: b = 3 \: \: }}}}[/tex]
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