Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

A custodian pushes a 119 kg box across a level floor. The box moves at a constant velocity. The custodian pushes horizontally on the box with a force of 724 Newtons, what must be the friction force experienced by the box in Newtons?

Sagot :

abidemiokin

The friction force experienced by the box in Newtons is 724N

The frictional force is the force that opposes the moving force acting on a body on a horizontal plane.

  • For a static body, the acceleration will be zero,

According to Newton's second law of motion:

  • ∑Fx = ma
  • +Fm - Ff = ma

Given the following paramters

  • Moving force Fm = 724N
  • acceleration a = 0m/s²
  • mass m = 119 kg

Substitute the given parameters into the formula to get the frictional force:

724 - Ff = 119(0)

724 - Ff = 0

Ff = 0 + 724

Ff = 724N

Hence the friction force experienced by the box in Newtons is 724N

Learn more here: https://brainly.com/question/8859573

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.