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The length of a rectangle is twice it’s width. If the area of the rectangle is 162m ^2,find its perimeter

Sagot :

Answer:

[tex]{ \tt{area = length \times width}} \\ { \tt{162 = 2w \times w}} \\ { \tt{162 = 2 {w}^{2} }} \\ { \tt{ {w}^{2} = 81}} \\ { \tt{w = 9}}[/tex]

  • width, w = 9 m
  • length, l = 2 × 9 = 18 m

[tex]{ \tt{perimeter = 2(l + w)}} \\ { \tt{p = 2(18 + 9)}} \\ { \tt{p = 2 \times 27}} \\ \\ { \underline{ \tt{ \: \: perimeter = 54 \: m \: \: }}}[/tex]

coldprince

Answer:

54 m

Step-by-step explanation:

First, find the width

　162 = 2w × w

　162 = 2w²

　w² = 162 ÷ 2

　w = [tex] \sqrt{81}[/tex]

　w = 9 m

┈

Second, find the length

　l = w × 2

　l = 9 × 2

　l = 18 m

┈

Then, find the perimeter

　perimeter = 2(l + w)

　perimeter = 2(18 + 9)

　perimeter = 2(27)

　perimeter = 54 m

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