Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

The length of a rectangle is twice it’s width. If the area of the rectangle is 162m ^2,find its perimeter

Sagot :

Answer:

[tex]{ \tt{area = length \times width}} \\ { \tt{162 = 2w \times w}} \\ { \tt{162 = 2 {w}^{2} }} \\ { \tt{ {w}^{2} = 81}} \\ { \tt{w = 9}}[/tex]

  • width, w = 9 m
  • length, l = 2 × 9 = 18 m

[tex]{ \tt{perimeter = 2(l + w)}} \\ { \tt{p = 2(18 + 9)}} \\ { \tt{p = 2 \times 27}} \\ \\ { \underline{ \tt{ \: \: perimeter = 54 \: m \: \: }}}[/tex]

coldprince

Answer:

54 m

Step-by-step explanation:

First, find the width

　162 = 2w × w

　162 = 2w²

　w² = 162 ÷ 2

　w = [tex] \sqrt{81}[/tex]

　w = 9 m

┈

Second, find the length

　l = w × 2

　l = 9 × 2

　l = 18 m

┈

Then, find the perimeter

　perimeter = 2(l + w)

　perimeter = 2(18 + 9)

　perimeter = 2(27)

　perimeter = 54 m

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.