Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Write the slope-intercept form of the line that passes through (1, -2) and is parallel to the line y = 4x + 2.

Sagot :

Use

y-y1=m(x-x1)

y-(-2)=4(x-1) Now why 4??Because parallel lines have the exact same slope

y+2=4x-4

y=4x-4-2

y=4x-6

Hope it helps!

[tex]GraceRosalia[/tex]

~Just a teen who listens to music

Parallel lines have the same slope.

Given the linear equation, y = 4x + 2:

Since the slope = 4, then we can assume that the slope of the line parallel to y = 4x + 2 will have the same slope.

We’ll use this slope and the given point, (1,-2), and plug these values into the slope-intercept form (y = mx + b) to solve for the y-intercept (b):

y = mx + b
-2 = 4(1) + b
-2 = 4 + b

Subtract 4 from both sides to isolate and solve for b:

-2 - 4 = 4 - 4 + b
-6 = b

Therefore, the y-coordinate of the y-intercept is -6 . Now, we can finally establish the linear equation of the line parallel to y = 4x + 2, which is:

y = 4x - 6.

Attached is a screenshot of the graph of both equations to show that we came up with a line parallel to the original equation.

Please mark my answers as the Brainliest if you find my explanations helpful :)
View image djtwinx017