Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A flagpole stands on the edge of vertical cliff. From a point 30 m away from the cliff, the angle of elevation of the top of the flagpole is 35° and that of the top of cliff is 20°. How tall is the flagpole to the nearest metre? Give your answer, in metres.

Sagot :

The flagpole is 35.43 meters tall

Distance of the flag from the cliff is 30m

Angle of elevation to the flagpole is 35°

Angle of elevation to the top of the cliff is 20°

To solve this we would apply the sine rule.

The sine rule states that [tex]\frac{sin A}{a} = \frac{sin B}{B}[/tex]

Taking a look at the attached image, we see that

b = 30

B = 70°

a = ?

A = 20°

Applying the formula, we have

[tex]\frac{sin20}{a} = \frac{sin 70}{30}[/tex]

asin(70) = 30sin(20)

a = [tex]\frac{30sin20}{sin70}[/tex]

a = [tex]\frac{27.388}{0.773}[/tex]

a = 35.43 meters

View image barackodam
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.