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If m FDE= (3x-15) and m FDB= (5x+59), find the value of x such that FDE and FDB are supplementary

Sagot :

MrRoyal

Supplementary angles add up to 180 degrees

The value of x is 17

The given parameters are:

[tex]FDE = 3x - 15[/tex]

[tex]FDB = 5x + 59[/tex]

Because the angles are supplementary, then:

[tex]FDE + FDB = 180[/tex]

So, we have:

[tex]3x - 15 + 5x + 59 = 180[/tex]

Collect like terms

[tex]3x + 5x = 15 - 59 + 180[/tex]

[tex]8x = 136[/tex]

Divide both sides by 8

[tex]x = 17[/tex]

Hence, the value of x is 17

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