Answer:
[tex]\displaystyle F'(0) = 15[/tex]
Step-by-step explanation:
We are given that:
[tex]f'(0) = 5 \text{ and } F(x) = f(3x)[/tex]
And we want to find F'(0).
First, find F(x):
[tex]\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)][/tex]
From the chain rule:
[tex]\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}[/tex]
Then:
[tex]\displaystyle \begin{aligned} F'(0) & = 3f'(3(0)) \\ \\ & = 3f'(0) \\ \\ & = 3(5) \\ \\ & = 15\end{aligned}[/tex]
In conclusion, F'(0) = 15.
Answer:
F'(0)=15
Step-by-step explanation:
Differentiate [tex]F(x)[/tex] with respect to [tex]x[/tex].
[tex]F'(x)=3f'(x)[/tex]
Subsitute [tex]0[/tex] for [tex]x[/tex] in the above equation.
[tex]F'(0)=3f'(0)\\=3\cdot5\\=15[/tex]
