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find two numbers with a sum of 104 and a difference of 42

Sagot :

kittyhumanlover

Answer:

31 and 73

Step-by-step explanation:

Writing this is variable form,

x+y = 104

x-y = 42

If we use the process of elimination and add the system of equations together;

2x = 146

x = 73

Substituting that back in;

x - y = 42

(73) - y = 42

y = 31

Answer:

[tex]a=73 \text{ and } b=31[/tex]

Step-by-step explanation:

[tex]a+b=104 --- (1)\\a-b=42 ---(2)\\[/tex]

Add (1) and (2), we get

[tex]2a=104+42\\a=\dfrac{146}{2}\\=73[/tex]

[tex]73-b=42\\-b=42-73\\b=31[/tex]

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