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The midpoint of the line segment from P4 to P2 is (-5,1). If P1 = (-7,9), what is P2?

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pneha7520

Let A(2,0),B(0,92)

Let A(2,0),B(0,92)and let mid-point be C(1,3p)

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞⇒(1,3p)=(1,91)

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞⇒(1,3p)=(1,91)Comparing y-coordinate

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞⇒(1,3p)=(1,91)Comparing y-coordinate3p=91

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞⇒(1,3p)=(1,91)Comparing y-coordinate3p=91∴p=31

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞⇒(1,3p)=(1,91)Comparing y-coordinate3p=91∴p=31We need to show that line 5x+3y+2=0 passes through point (−1,3p)

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞⇒(1,3p)=(1,91)Comparing y-coordinate3p=91∴p=31We need to show that line 5x+3y+2=0 passes through point (−1,3p)Point =(−1,3p)=(−1,3×31)=(−1,1)

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞⇒(1,3p)=(1,91)Comparing y-coordinate3p=91∴p=31We need to show that line 5x+3y+2=0 passes through point (−1,3p)Point =(−1,3p)=(−1,3×31)=(−1,1)Putting (−1,1) in line

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞⇒(1,3p)=(1,91)Comparing y-coordinate3p=91∴p=31We need to show that line 5x+3y+2=0 passes through point (−1,3p)Point =(−1,3p)=(−1,3×31)=(−1,1)Putting (−1,1) in line5x+3y+2=0

Let A(2,0),B(0,92)and let mid-point be C(1,3p)Finding coordinates of C(1,3p)=⎝⎜⎜⎛22+0,20+92⎠⎟⎟⎞⇒(1,3p)=(1,91)Comparing y-coordinate3p=91∴p=31We need to show that line 5x+3y+2=0 passes through point (−1,3p)Point =(−1,3p)=(−1,3×31)=(−1,1)Putting (−1,1) in line5x+3y+2=0⇒5(−1)+3(1)+2=0

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