allyboltorumny586
Answered

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Solve the following quadratic equations by factoring. Show your solutions 2. ײ+2×=-1​

Sagot :

Step-by-step explanation:

x²+2x=-1

x²+2x+1=0

x²+x+x+1=0

x(x+1)+1(x+1)=0

(x+1)(x+1)=0

(x+1)²=0

x+1=0

x=-1

DᴀʀᴋPᴀʀᴀᴅᴏx

let's solve :

  • [tex] {x}^{2} + 2x + 1 = 0[/tex]

  • [tex]x {}^{2} + x + x + 1 = 0[/tex]

  • [tex]x(x + 1) + 1(x + 1) = 0[/tex]

  • [tex](x + 1)(x + 1) = 0[/tex]

  • [tex](x + 1) {}^{2} = 0[/tex]

  • [tex]x + 1 = 0[/tex]

  • [tex]x = - 1[/tex]

hence, value of x = -1

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