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what is the net ionic equation for Li3PO4 and Ba(NO3)2 ?

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Eduard22sly

The net ionic equation for the reaction between Li₃PO₄ and Ba(NO₃)₂ is:

2PO₄³¯(aq) + 3Ba²⁺(aq) —>  Ba₃(PO₄)₂(s)

In solution, Li₃PO₄ and Ba(NO₃)₂ will dissociate as follow:

Li₃PO₄ (aq) —> 3Li⁺(aq) + PO₄³¯(aq)

Ba(NO₃)₂ (aq) —> Ba²⁺(aq) + 2NO₃¯(aq)

The reaction will proceed as follow:

Li₃PO₄(aq) + Ba(NO₃)₂(aq) —>

3Li⁺(aq) + PO₄³¯(aq) + Ba²⁺(aq) + 2NO₃¯(aq) —> 3Li⁺(aq) + 2NO₃¯(aq) + Ba₃(PO₄)₂(s)

Cancel the spectator ions (i.e Li⁺ and NO₃¯)

PO₄³¯(aq) + Ba²⁺(aq) —>  Ba₃(PO₄)₂(s)

Balacing the equation above, we have:

2PO₄³¯(aq) + 3Ba²⁺(aq) —>  Ba₃(PO₄)₂(s)

Therefore, the net ionic equation for the reaction between Li₃PO₄ and Ba(NO₃)₂ is:

2PO₄³¯(aq) + 3Ba²⁺(aq) —>  Ba₃(PO₄)₂(s)

Learn more: https://brainly.com/question/16981518

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