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Solve the attached sum (Trigonometry)

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Solve The Attached Sum Trigonometry class=

Sagot :

Medunno13

Answer: [tex]\sec \theta[/tex]

Step-by-step explanation:

The period of [tex]\sec \theta[/tex] is [tex]2\pi[/tex], so [tex]\sec(4\pi -\theta)=\sec(-\theta)[/tex]

Also, as [tex]\sec \theta[/tex] is an even function, [tex]\sec(-\theta)=\boxed{\sec \theta}[/tex]

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