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Sagot :
The change in density of water is -41.82 kg/m³
The given parameters;
- initial temperature of the water, = 15°C
- final temperature of the water, = 100 °C
- density of water at 1 atm, ρ = 999.9 kg/m³
The change in density of water using coefficient of volume expansion is given as;
[tex]\Delta \rho = -\beta \rho \Delta T[/tex]
where;
[tex]\beta[/tex] is the coefficient of volume expansion of water
the average temperature of 15 °C and 100 °C = 57.5
the coefficient of volume expansion of water = 0.492 x 10⁻⁴ K⁻¹
The change in density of water is calculated as;
[tex]\Delta \rho = -\beta \rho \Delta T\\\\\Delta \rho = -(4.92\times 10^{-4} ) (999.9)(100-15)\\\\\Delta \rho = -41.82 \ kg/m^3[/tex]
Thus, the change in density of water is -41.82 kg/m³
Learn more here: https://brainly.com/question/13961424
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