Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Part D
Complete the table to find the rule for the dilation, the coordinates of trapezoid P′Q′R′S′, and the coordinates of the dilated image, trapezoid P″Q″R″S″.


Part D Complete The Table To Find The Rule For The Dilation The Coordinates Of Trapezoid PQRS And The Coordinates Of The Dilated Image Trapezoid PQRS class=
Part D Complete The Table To Find The Rule For The Dilation The Coordinates Of Trapezoid PQRS And The Coordinates Of The Dilated Image Trapezoid PQRS class=

Sagot :

The shrink or stretch of the image of PQRS which is the dilation of PQRS is given as follows;

  • The rule of the dilation is [tex]\underline{D_{\frac{1}{2} }}[/tex], followed by a reflection across the x-axis

Reason:

The given completed  table is presented as follows;

[tex]\begin{array}{|cc|c|} \mathbf{Original \ Coordinates}&&\mathbf{New \ Coordinates}\\(x, \ y)&&(,)\\K(3, \, 2)&&P(6, \, -4)\\L(1, \, 1)&&Q(2, \, -2)\\M(1, \, 3)&&R(2, \, -6)\\N(3, \, 3)&&S(6, \, -6)\end{array}[/tex]

Length of the side [tex]\overline{LM}[/tex] = 3 - 1 = 2

Length of the side [tex]\overline{MN}[/tex] = 3 - 1 = 2

Length of the side [tex]\overline{NK}[/tex] = 3 - 2 = 1

Length of the side [tex]\overline{LK}[/tex] = [tex]\sqrt{(2 - 1)^2 + (3 - 1)^2} = \sqrt{5}[/tex]

Length of the side [tex]\overline{RQ}[/tex] = -2 - (-6) = 4

Length of the side [tex]\overline{RS}[/tex] = 6 - 2 = 4

Length of the side [tex]\overline{SP}[/tex] = -4 - (-6) = 2

Length of the side [tex]\overline{QP}[/tex] = [tex]\sqrt{(6 - 2)^2 + (-4 - (-2))^2} = 2\cdot \sqrt{5}[/tex]

[tex]\dfrac{\overline{LM}}{\overline{RQ}} = \dfrac{\overline{MN}}{\overline{RS}} = \dfrac{\overline{NK}}{\overline{SP}} = \dfrac{\overline{LK}}{\overline{QP}} = \dfrac{1}{2}[/tex]

However, the coordinates of the image of PQRS, which is P'Q'R'S', following a dilation are'

[tex]P' \left(\dfrac{1}{2} \times 6, \, \dfrac{1}{2} \times (-4) \right) = P'(3, \, -2)[/tex]

[tex]Q' \left(\dfrac{1}{2} \times 2, \, \dfrac{1}{2} \times (-2) \right) = Q'(1, \, -1)[/tex]

[tex]R' \left(\dfrac{1}{2} \times 2, \, \dfrac{1}{2} \times (-6) \right) = R'(1, \, -3)[/tex]

[tex]S' \left(\dfrac{1}{2} \times 6, \, \dfrac{1}{2} \times (-6) \right) = S'(3, \, -3)[/tex]  

The transformation of the coordinates of P'Q'R'S', to KLMN are;

  • (x, y) → (x, -y)

which is equivalent to a reflection across the x-axis

Therefore, the transformation that gives the coordinate of KLMN from PQRS is a dilation by a scale factor of [tex]\underline{\dfrac{1}{2}}[/tex], which is a rule of dilation of [tex]\underline{D_{\frac{1}{2} }}[/tex], followed by a reflection across the x-axis

Learn more here:

https://brainly.com/question/12382913

Answer:

Original / New

P′(4 , 6)  P″(2 , 3)

Q′(2 , 2) Q″(1 , 1)

R′(6 , 2)  R″(3 , 1)

S′(6 , 6) S″(3 , 3)

I hope this helps :)

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.