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Sagot :
Answer:
• First term, a1 = 24
• Last term, l = 68
- → From the general A.P formular;
[tex]{ \boxed{ \rm{l = a _{1} + (n - 1)d}}} \\ [/tex]
• Therefore:
[tex]{ \rm{mean = \frac{1}{2} (a _{1} + l)}} \\ \\ { \rm{mean = \frac{1}{2}(24 + 68) }} \\ \\ { \boxed{ \rm{mean = 46 \: terms}}}[/tex]
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