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what is an equation for the line perpendicular to y=-1/8x+6 that passes through (-3,-10)

Sagot :

Answer:

y = 8x + 14

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - [tex]\frac{1}{8}[/tex] x + 6 ← is in slope- intercept form

with slope m = - [tex]\frac{1}{8}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{8} }[/tex] = 8 , then

y = 8x + c ← is the partial equation

To find c substitute (- 3, - 10 ) into the partial equation

- 10 = - 24 + c ⇒ c = - 10 + 24 = 14

y = 8x + 14 ← equation of perpendicular line

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