Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
If a circle has a radius of [tex](6x + 11)[/tex], it is true that: D. The circumference of the circle is [tex](12x + 22) \pi $ cm[/tex]
Recall the following about a circle:
- Area of a circle = [tex]\pi r^2[/tex]
- Circumference of a circle = [tex]2 \pi r[/tex]
If a circle has a radius of [tex](6x+11) $ cm[/tex], the area and circumference of the circle would be the following:
- Area of a circle = [tex]\pi r^2[/tex]
- Substitute [tex]r = (6x+11)[/tex] into the area formula
[tex]\pi (6x + 11)^2[/tex]
- Expand
[tex]\pi \times (6x + 11) \times (6x + 11)\\\\\pi \times(36x^2 + 66x + 66x + 121)\\\\\pi \times (36x^2 + 132x + 121)\\\\ area = (36x^2 + 132x + 121) \pi $ cm^2[/tex]
- Circumference of a circle = [tex]2 \pi r[/tex]
- Substitute [tex]r = (6x+11)[/tex] into the circumference formula
[tex]2 \times \pi \times (6x + 11)\\\\Circumference = (12x + 22) \pi[/tex]
Therefore, if a circle has a radius of [tex](6x + 11)[/tex], it is true that: D. The circumference of the circle is [tex](12x + 22) \pi $ cm[/tex]
Learn more here:
https://brainly.com/question/14772815
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
