Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

50 Points Help

1) Find the mass of 250.0 mL of benzene. The density of benzene is 0.8765 g/mL.

7) What volume of silver metal will weigh exactly 2500.0 g. The density of silver is 10.5 g/cm3.


Sagot :

1. Find mass of 250.0 ml of benzene : -

given data :

  • density = 0.8765 g/ml

  • volume = 250 ml

we know the relation between mass, volume and density

that is

[tex] \boxed{ \boxed{density = \dfrac{mass}{volume} }}[/tex]

  • [tex]0.8765 = \dfrac{m}{250} [/tex]

  • [tex]m = 250 \times 0.8765[/tex]

  • [tex]m = 219.125 \: \: grams[/tex]

  • [tex] \approx219.12 \: g[/tex]

7. Find volume of silver metal :

given data :

  • mass = 2500.0 g

  • density = 10.5 g/ cm³

Since we already know the relation, let's solve form volume :

  • [tex]10.5 = \dfrac{2500}{v} [/tex]

  • [tex]v = \dfrac{2500}{10.5} [/tex]

  • [tex]v = 238.095 \: \: cm {}^{3} [/tex]

  • [tex] \approx238.1 \: \: cm {}^{3} [/tex]
  • Volume=250mL
  • Density=0.8765g/mL

[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]

[tex]\\ \sf\longmapsto Mass=Density\times volume[/tex]

[tex]\\ \sf\longmapsto Mass=250(0.8765)[/tex]

[tex]\\ \sf\longmapsto Mass=219.12g[/tex]

#2

  • Mass=2500g
  • Density=10.5g/cm^3

[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]

[tex]\\ \sf\longmapsto Volume=\dfrac{Mass}{Density}[/tex]

[tex]\\ \sf\longmapsto Volume=\dfrac{2500}{10.5}[/tex]

[tex]\\ \sf\longmapsto Volume=238.09cm^3[/tex]

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.