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Sagot :
1. Find mass of 250.0 ml of benzene : -
given data :
- density = 0.8765 g/ml
- volume = 250 ml
we know the relation between mass, volume and density
that is
[tex] \boxed{ \boxed{density = \dfrac{mass}{volume} }}[/tex]
- [tex]0.8765 = \dfrac{m}{250} [/tex]
- [tex]m = 250 \times 0.8765[/tex]
- [tex]m = 219.125 \: \: grams[/tex]
- [tex] \approx219.12 \: g[/tex]
7. Find volume of silver metal :
given data :
- mass = 2500.0 g
- density = 10.5 g/ cm³
Since we already know the relation, let's solve form volume :
- [tex]10.5 = \dfrac{2500}{v} [/tex]
- [tex]v = \dfrac{2500}{10.5} [/tex]
- [tex]v = 238.095 \: \: cm {}^{3} [/tex]
- [tex] \approx238.1 \: \: cm {}^{3} [/tex]
- Volume=250mL
- Density=0.8765g/mL
[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]
[tex]\\ \sf\longmapsto Mass=Density\times volume[/tex]
[tex]\\ \sf\longmapsto Mass=250(0.8765)[/tex]
[tex]\\ \sf\longmapsto Mass=219.12g[/tex]
#2
- Mass=2500g
- Density=10.5g/cm^3
[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]
[tex]\\ \sf\longmapsto Volume=\dfrac{Mass}{Density}[/tex]
[tex]\\ \sf\longmapsto Volume=\dfrac{2500}{10.5}[/tex]
[tex]\\ \sf\longmapsto Volume=238.09cm^3[/tex]
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