Answered

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An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws the rock straight up with a velocity of + 15 m/s and measures a time of 20.0 seconds before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet?

Sagot :

The time 20s is for the rock to move up and move down back to the hand.
So we need to divide by 2.
Hence, t = 10s
a = +15m/s / 10s
a = +1.5 m/s2
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