Yahami
Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Q). The degree of (- 1/20 x⁴y³) × (- 5 x⁷y²) is​

Q The Degree Of 120 Xy 5 Xy Is class=

Sagot :

Step-by-step explanation:

[tex]\large\underline{\sf{Given \:Question - }}[/tex]

The degree of

[tex]\rm :\longmapsto\:\bigg( - \dfrac{1}{20} {x}^{4} {y}^{3}\bigg) \times \bigg( - 5 {x}^{7} {y}^{2} \bigg) [/tex]

[tex]\green{\large\underline{\sf{Solution-}}}[/tex]

Given polynomial is

[tex]\rm :\longmapsto\:\bigg( - \dfrac{1}{20} {x}^{4} {y}^{3}\bigg) \times \bigg( - 5 {x}^{7} {y}^{2} \bigg) [/tex]

can be regrouped as

[tex]\rm \:  =  \: \bigg( - \dfrac{1}{20} \times ( - 5) \bigg) \times \bigg( {x}^{4} \times {x}^{7}\bigg) \times \bigg( {y}^{3} \times {y}^{2} \bigg) [/tex]

We know,

[tex]\red{\rm :\longmapsto\:\boxed{\tt{ {x}^{m} \: \times \: {x}^{n} \: = \: {x}^{m \: + \: n} \: }}}[/tex]

So,

[tex]\rm \:  =  \: \dfrac{1}{4} \times {x}^{4 + 7} \times {y}^{3 + 2} [/tex]

[tex]\rm \:  =  \: \dfrac{1}{4} \times {x}^{11} \times {y}^{5} [/tex]

[tex]\rm \:  =  \: \dfrac{ {x}^{11} \times {y}^{5} }{4} [/tex]

[tex]\rm \:  =  \: \dfrac{ {x}^{11} \: {y}^{5} }{4} [/tex]

Thus,

[tex]\rm :\longmapsto\:\boxed{\tt{ \bigg( - \dfrac{1}{20} {x}^{4} {y}^{3}\bigg) \times \bigg( - 5 {x}^{7} {y}^{2} \bigg) = \frac{ {x}^{11} \: {y}^{5} }{4} \: }}[/tex]

So, Degree of polynomial expression is 16.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Learn More :-

[tex]\boxed{\tt{ {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}[/tex]

[tex]\boxed{\tt{ {x}^{m} \div {x}^{n} = {x}^{m - n} \: }}[/tex]

[tex]\boxed{\tt{ {( {x}^{m}) }^{n} \: = \: {x}^{mn} \: }}[/tex]

[tex]\boxed{\tt{ {x}^{0} = 1 \: }}[/tex]

[tex]\boxed{\tt{ {x}^{ - n} \: = \: \frac{1}{ {x}^{n} } \: }}[/tex]