Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Applying the limit to the function, it is found that it is equivalent to 2.
The function is given by:
[tex]f(x) = \sin{x} - \cos{2x}[/tex]
It has no discontinuities, so the limit is found just replacing each instance of x by the value the limit is tending, which in this case is [tex]\frac{\pi}{2}[/tex]. Then:
[tex]\lim_{x \rightarrow \frac{\pi}{2}} f(x) = \lim_{x \rightarrow \frac{\pi}{2}} \sin{x} - \cos{2x} = \sin{\frac{\pi}{2}} - \cos{2\frac{\pi}{2}} = 1 - \cos{\pi} = 1 - (-1) = 2[/tex]
This all means that the limit is equivalent to 2.
A similar problem is given at https://brainly.com/question/23882529
Answer: a) lim x--^ pi/2. -1/1+sinx
Explanation:
College board unit 1 progress check
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.