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Sagot :
Applying the limit to the function, it is found that it is equivalent to 2.
The function is given by:
[tex]f(x) = \sin{x} - \cos{2x}[/tex]
It has no discontinuities, so the limit is found just replacing each instance of x by the value the limit is tending, which in this case is [tex]\frac{\pi}{2}[/tex]. Then:
[tex]\lim_{x \rightarrow \frac{\pi}{2}} f(x) = \lim_{x \rightarrow \frac{\pi}{2}} \sin{x} - \cos{2x} = \sin{\frac{\pi}{2}} - \cos{2\frac{\pi}{2}} = 1 - \cos{\pi} = 1 - (-1) = 2[/tex]
This all means that the limit is equivalent to 2.
A similar problem is given at https://brainly.com/question/23882529
Answer: a) lim x--^ pi/2. -1/1+sinx
Explanation:
College board unit 1 progress check
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