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Solve a system of linear equations to find that values of x and y
m<2y m<4x m<(2x + 12) m<(y + 6)

The linear equations are 4x + ___ = 180 and 2x + ___ = 180
The solutions are x = ___ and y = ___

Sagot :

The solutions to the systems of equations are x = 30 and y = 54

The correct linear equation is expressed as:

4x+y+6=180 ................1

2x+2y+12=180 .................2

The equations can also be written as:

4x + y = 174 .................... 3 × 2

2x + 2y = 168 ................... 4 × 1

______________________________________

8x + 2y = 348

2x + 2y = 168

Subtract both equations

8x - 2x = 348 - 168

6x = 180

x = 180/6

x = 30

Substitute x = 30 into equation 3:

4x + y = 174

4(30) + y = 174

120 + y = 174

y = 174 - 120

y = 54

Therefore the solutions are x = 30 and y = 54

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