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Sienna used the scale drawing above to create a pool that is 14 ft wide x 22 ft long. She then decided to make pool with a final length of 33 ft. Which expression finds the change in scale factor for the longer pool with a final length of 33 ft which expression finds the change in scale factor for the longer pool Sierra is building​

Sienna Used The Scale Drawing Above To Create A Pool That Is 14 Ft Wide X 22 Ft Long She Then Decided To Make Pool With A Final Length Of 33 Ft Which Expression class=

Sagot :

A scale factor allows a shape to be changes into another shape by changing  the linear dimensions to the multiples of the initial dimension and a constant

The expression that finds the change in scale factor for the longer pool with a final length of 33 ft. Sierra is building is the option;

  • [tex]\dfrac{2 \, ft.}{3 \, ft.}[/tex]

Reason:

Known parameters are;

Dimensions of the pool created = 14 ft. wide Ă— 22 ft. long

Final length of the pool = 33 ft.

Let x represent the length of the drawing using the initial scale factor, we have;

  • [tex]The \ initial \ scale \ factor = \dfrac{22 \, ft.}{x \, in.}[/tex]

The scale factor of the drawing following a final length of 33 ft. is therefore;

  • [tex]New \ scale \ factor = \dfrac{33 \, ft.}{x \, in.}[/tex]

The change in scale factor is given as follows;

[tex]Change \ in \ scale \ factor = \dfrac{Initial \, scale \, factor}{Final \, scale \, factor}[/tex]

Therefore;

  • [tex]Change \ in \ scale \ factor = \frac{\left( \dfrac{22 \, ft.}{x \, in.} \right)}{\left( \dfrac{33 \, ft.}{x \, in.} \right)} = \dfrac{2 \, ft.}{3 \, ft.}[/tex]

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Liyahdiorrr

Answer:

It's c

Step-by-step explanation:

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