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The length of a rectangle is 4ft longer than it’s width if the perimeter of the rectangle is 68 ft find the length and width

Sagot :

adioabiola

The question requires we find the length and width of the rectangle

The length and width of the rectangle is

19 ft and 15 ft respectively

Perimeter of a rectangle = 2(length + width)

let

width of the rectangle = x

Length of the rectangle = (x + 4) ft

perimeter of the rectangle = 68ft

Perimeter of a rectangle = 2(length + width)

68 = 2{(x + 4) + x}

68 = 2(x + 4 + x)

68 = 2(2x + 4)

68 = 4x + 8

68 - 8 = 4x

60 = 4x

divide both sides by 4

60/4 = x

x = 15

Therefore,

width of the rectangle = x

= 15 ft

Length of the rectangle = (x + 4) ft

= (15 + 4)

= 19 ft

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