imathgud
Answered

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Write an equation of a parabola with x-intercepts at (1/4,0) and (-7,0) which passes through the point (0,7).

Sagot :

Answer:

f(x) = - 4x² - 27x + 7

Step-by-step explanation:

f(x) = a*(x-1/4)(x+7) = a(x² + 27/4 x - 7/4)

pass (0,7):   7 = a (-7/4)

a = -4

f(x) = -4*(x² + 27/4 x - 7/4)

f(x) = -4x² - 27x + 7

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