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The points (–7, 7) and (6, –6) fall on a particular line. What is its equation in slope-intercept form?

Sagot :

Leora03

Answer:

y= -x

Step-by-step explanation:

Slope-intercept form

y= mx +c, where m is the slope and c is the y-intercept

[tex]\boxed{slope = \frac{y1 - y2}{x1 - x2} }[/tex]

Slope

[tex] = \frac{7 - ( - 6)}{ - 7 - 6} [/tex]

[tex] = \frac{7 + 6}{ - 13} [/tex]

[tex] = \frac{13}{ - 13} [/tex]

[tex] = - 1[/tex]

Substitute m= -1 into the equation:

y= -1x +c

y= -x +c

To find the value of c, substitute a pair of coordinates.

When x= -7, y= 7,

7= -(-7) +c

7= 7 +c

c= 7 -7

c= 0

Thus, the equation of the line is y= -x.

apradhan49

Answer:

y=-x

Step-by-step explanation:

Slope =1

Substitute m= -1 into the equation:

y= -1x +c

y= -x +c

To find the value of c, substitute a pair of coordinates.

When x= -7, y= 7,

7= -(-7) +c

7= 7 +c

c= 7 -7

c= 0

Thus, the equation of the line is y= -x.

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