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Find whole number values for h and the length of the missing shorter base.

h

A = 40 cm2

42

8 cm

centimeters, shorter base = centimeters.

Sagot :

The area of a shape is the amount of space the shape can occupy.

The values of the height and the shorter base are: 8cm and 2cm respectively

The given dimensions are:

[tex]\mathbf{Area = 40cm^2}[/tex]

[tex]\mathbf{Base = 8cm}[/tex]

The area of a trapezoid (see attachment) is:

[tex]\mathbf{Area = \frac 12(Base_1 + Base_2) \times Height}[/tex]

So, we have:

[tex]\mathbf{40 = \frac 12(8 + Base_2) \times Height}[/tex]

Multiply through by 2

[tex]\mathbf{80 = (8 + Base_2) \times Height}[/tex]

The whole number values of base and height that satisfy the above equation is:

[tex]\mathbf{Base_2 = 2}[/tex]

[tex]\mathbf{Height = 8}[/tex]

i.e.

[tex]\mathbf{80 = (8 + Base_2) \times Height}[/tex]

[tex]\mathbf{80 = (8 + 2) \times 8}[/tex]

[tex]\mathbf{80 = 10 \times 8}[/tex]

[tex]\mathbf{80 = 80}[/tex]

Hence, the values of the height and the shorter base are: 8cm and 2cm respectively

Read more about areas at:

https://brainly.com/question/16418397

View image MrRoyal