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Sagot :
The density of the rectangular block in g/mL is 7.0.
Given the following data:
- Mass of block = 22.8 gra1.94 kg
- Length of block = 3.21 cm
- Width of block = 5.83 cm
- Height of block = 1.84 in.
To find the density of the block in g/mL:
First of all, we would determine the volume of the rectangular block by using the following formula:
[tex]Volume = length[/tex] × [tex]width[/tex] × [tex]height[/tex]
Conversion:
1 in = 2.54 cm
5.83 in = X cm
Cross-multiplying, we have:
[tex]X = 2.54(5.83)\\\\X = 14.81 \; cm[/tex]
[tex]Volume = 3.21[/tex] × [tex]5.83[/tex] × [tex]14.81[/tex]
Volume = 277.16 cubic centimeters.
Note: Milliliter (mL) is the same as cubic centimeters.
1000 grams = 1 kg
Y grams = 1.94 kg
Cross-multiplying, we have:
Y = 1940 grams
Now, we can find the density:
[tex]Density = \frac{Mass}{Volume}\\\\Density = \frac{1940}{277.16}[/tex]
Density = 7.0 g/mL
Therefore, the density of the rectangular block in g/mL is 7.0.
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