If you react 3 moles of reactant A with 1 moles of reactant B, 2 moles of reactant A will be remaining.
From the question given above, the balanced equation for the reaction between reactant A and B is given below:
A + B —> C
1 : 1
3 : 1
From the balanced equation above,
1 mole of A reacted with 1 mole of B.
Therefore,
3 moles of A will also react with 3 moles of B.
Thus, B is the limiting reactant and A is the excess reactant.
Finally, we shall determine amount of A remaining.
Amount of A given = 3 moles
Amount of A that reacted = 1 mole
Amount of A remaining =?
Amount of A remaining = (Amount of A given) – (Amount of A that reacted)
Amount of A remaining = 3 – 1
Amount of A remaining = 2 moles
Therefore, 2 moles of reactant A will remain if 3 moles of reactant A with 1 moles of reactant B.
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