DᴀʀᴋPᴀʀᴀᴅᴏx
Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

I need help with this question !​

I Need Help With This Question class=

Sagot :

msm555

Answer:

Solutions given:

[tex] \frac{SinA}{SinB}=p[/tex]

SinA=pSin B or

Sin B=Sin A/p

[tex]\frac{CosA}{CosB}=q[/tex]

Cos A=qCos B

or

Cos B=Cos A /q

now

TanA=[tex]\frac{Sin A}{Cos A}=\frac{psinB}{qCosB}=\frac{p}{q}*TanB[/tex]

again

TanB=[tex]\frac{Sin B}{Cos B}=\frac{Sin A /p}{CosA/q}=\frac{q}{p} Tan A[/tex]

now

[tex]\frac{TanA}{TanB}=\frac{p}{q}[/tex]

Refer to the attachment

View image Аноним
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.