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Sagot :
(3x + 2) < -7 or (3x + 2 >7
Explanation/Step by step:
We have| |3x +2| >7
We divide the absolute value inequality into two inequalities
First Inequality (Which is Positive Value)
(3x + 2) >7
Second inequality (Which is the Negative Value)
-(3x + 2) >7
Then you Multiply by- 1 both sides
~And Remember that when you multiply or divide both sides of an inequality by a negative number you must reverse the inequality Symbol.~
So which that be said it would look like this:
(3x +2) < -7
So therefore (3x + 2) < -7 or (3x + 2) >7
Hope this makes since to you!!
I hope this helps as well..
Explanation/Step by step:
We have| |3x +2| >7
We divide the absolute value inequality into two inequalities
First Inequality (Which is Positive Value)
(3x + 2) >7
Second inequality (Which is the Negative Value)
-(3x + 2) >7
Then you Multiply by- 1 both sides
~And Remember that when you multiply or divide both sides of an inequality by a negative number you must reverse the inequality Symbol.~
So which that be said it would look like this:
(3x +2) < -7
So therefore (3x + 2) < -7 or (3x + 2) >7
Hope this makes since to you!!
I hope this helps as well..
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