Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A hand-crank generator inputs 160 Joules of energy into a light bulb over the course of 2.5 seconds. Calculate the power

Sagot :

Lanuel

The power being dissipated by the hand-crank generator is 94.12 Watts.

Given the following data:

  • Energy = 160 Joules.
  • Power = 2.5 seconds.

To find the power being dissipated by the hand-crank generator:

Mathematically, power is given by the formula;

[tex]Power = \frac{Energy}{Time}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Power = \frac{160}{1.70}[/tex]

Power = 94.12 Watts.

Therefore, the power being dissipated by the hand-crank generator is 94.12 Watts.

Read more: https://brainly.com/question/12193740

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.